3x^2-4x-3135=0

Solution for 3x^2-4x-3135=0 equation:

3x^2-4x-3135=0

a = 3; b = -4; c = -3135;
Δ = b2-4ac
Δ = -42-4·3·(-3135)
Δ = 37636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{37636}=194$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-194}{2*3}=\frac{-190}{6}
=-31+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+194}{2*3}=\frac{198}{6}
=33
$